Question

sin 2 A (tan A + cot A) = 2​

Answer 1

Answer:

true

Step-by-step explanation:

sin2A(tanA + cotA) =

2sinAcosA(sin^2A +cos^2A)/sinAcosA =

2sinAcosA/sinAcosA =

2

Answer 2

Answer:

2

steps are..

L.H.S(it is I take)

sin2A(sinA/cosA+cosA/sinA) //I know that tanA=sinA/cos A,cotA=cosA/sinA

sin2A[(sin^2A+cos^2A)/sinAcosA] // I know that sim^2A+cos^2A=1, notes here A can be any angle okay

sin2A(1/sinAcosA)

2sinAcisA×1/sinAcosA

=2(R.H.S)