sin^2+cos^2=1 prove
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Question-sin^2theta+cos^2theta=1
Answer=
Suppose Triangle ABC is an right angled triangle
Therefore,By applying Pythagoras theorem in triangle ABC
BC^2+AB^2=AC^2.........(I)
Dividing both the sides of (I) by AC^2
Therefore, BC^2+AB^2/AC^2=AC^2/AC^2
Therefore, BC^2/AC^2+AB^2/AC^2=1
Therefore, [BC/AC]^2+[AB/AC]^2=1
Therefore,(sintheta)^2+(costheta)^2=1....[(sintheta)^2 is written as sin^2theta and (costheta)^2 is written as cos^2theta]
ANSWER= Sin^2theta+cos^2theta=1
Hence Proved...
HOPE IT WILL HELPFUL....
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