Question

sin^2 ¢+cos^2¢=cosec^2¢

Answer 1

@ is denoted here to represent angle,

$sin^{2}@ + cos^{2} = cosec^{2} @$

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$sin^{2} @ + cos^{2} @ = 1 [identity ]$
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1 = $cosec^{2} @$   

$\sqrt{1} = cosec @$

[1 = cosec 90 ]


[tex]cosec 90 =cosec@

90 =@


then the angle is 90

i hope this will help you



-by ABHAY

Answer 2

Solution :
[tex]sin^2 \alpha + cos^2 \alpha = cosec^2 \alpha \\ =\ \textgreater \ cosec^2 \alpha = 1 \ [ \ Since, \ sin^2 \alpha + cos^2 \alpha = 1 \ ] \\ =\ \textgreater \ sin^2 \alpha = 1 \\ =\ \textgreater \ sin \alpha = +1 \ or \ -1 \\ =\ \textgreater \ \alpha = \frac{\pi}{2} \ or \ \frac{3 \pi}{2}[/tex]