Sin^2+ cos^2 =??
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Answer:
Sin^2+ cos^2 =1
Step-by-step explanation:
sin(x)=b/c
cos(x)=a/c
Pythagorean Theorem:
a^2+b^2=c^2
Sin^2(x)+cos^2(x)=a^2+b^2/c^2
Sin^2(x)+cos^2(x)=a^2+b^2/c^2=c^2/c^2=1
(divide both sides by sin^2x)
Sin^2x+cos^2x=1
Sin^2(x)/sin^2(x)+cos^2(x)/sin^2(x)=1/sin^2(x)
1+cot^2x=csc^2x
Divide both sides by cos^2x
Sin^2(x)/cos^2(x)+cos^2(x)/cos^2(x)=1/cos^2(x)
tan^2x+1=sec^2x
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