Math, asked by sumitagrahari2004, 4 months ago

Sin^2+ cos^2 =??
please help me​

Answers

Answered by emiliodelossantos247
0

Answer:

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Answered by rihan86
0

Answer:

Sin^2+ cos^2 =1

Step-by-step explanation:

sin(x)=b/c

cos(x)=a/c

Pythagorean Theorem:

a^2+b^2=c^2

Sin^2(x)+cos^2(x)=a^2+b^2/c^2

Sin^2(x)+cos^2(x)=a^2+b^2/c^2=c^2/c^2=1

(divide both sides by sin^2x)

Sin^2x+cos^2x=1

Sin^2(x)/sin^2(x)+cos^2(x)/sin^2(x)=1/sin^2(x)

1+cot^2x=csc^2x

Divide both sides by cos^2x

Sin^2(x)/cos^2(x)+cos^2(x)/cos^2(x)=1/cos^2(x)

tan^2x+1=sec^2x

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