Question

sin^2(cot^-1√1-x/1+x)​

Answer 1

So the problems ask to find and calculate the exact value of the trigonometric equation in the following equations and the best answers would be the following:

#1. sqrt(3)/3

#2. Arcsine of zero is 0

#3. x/sqrt(4-x^2)

I hope you are satisfied with my answer and feel free to ask for more if you have questions and further clarifications. Have a nice day

Answer 2

 

Answer:

Brainiest me

Step-by-step explanation:

Let y=  dxd

​  [sin  2(cot−1  

1+x 1−x)] = dxd

cosec 2  {cot 2 1+x  1−x  } 1=  dx d

​1+cot2   {cot−1  1+x  1−x} 1 =  dx d

​1+  1+x 1−x1 =dx d

1+x 2  1  =  dx d  [  2 1+x  ]  

Therefore, dx dy =2  1

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