Question

sin[π/2-sin^-1-1/2]​

Answer 1

Step-by-step explanation:

sin[π/2 -sin)^-1(-1/2)]

sin[π/2 -sin^-1(sin-π/6)]

sin[π/2 +π/6]

sin2π/3

=√3/2

Answer 2

Answer:

Please refer to the above attachment.

Thank you.