Question

sin[2 sin inverse (0.8)]​

Answer 1

Given :

$\sin(2\sin^{-1} (0.8))$

To find : the value = ?

Solution :

As we know that

$2\sin^{-1}x=\sin^{-1}(2x.\sqrt{1-x^2})$

So, it becomes:

$2\sin ^{-1}(0.8)=\sin^{-1}(2\times 0.8. \sqrt{1-(0.8)^2})=\sin^{-1}(0.96)$

Now, it becomes:

$\sin(\sin^{-1}(0.96)=0.96$

Hence, the required value is 0.96.