Question

sin 2 square 37 degree - cos 2 square 53 degree

Answer 1

right answer will be zero

Answer 2

$\sin^2 37^\circ-\cos^2 53^\circ=0$

Step-by-step explanation:

Given : Expression $\sin^2 37^\circ-\cos^2 53^\circ$

To find : Solve the expression ?

Solution :

$\sin^2 37^\circ-\cos^2 53^\circ$

We know that, $\sin(90-\theta)=\cos \theta$

So, $\sin 37=\sin(90-53)=\cos 53$

$\sin^2 37^\circ-\cos^2 53^\circ=(\sin 37^\circ)^2-(\cos 53^\circ)^2$

$\sin^2 37^\circ-\cos^2 53^\circ=(\cos 53)^2-(\cos 53^\circ)^2$

$\sin^2 37^\circ-\cos^2 53^\circ=\cos^2 53-\cos^2 53^\circ$

$\sin^2 37^\circ-\cos^2 53^\circ=0$

#Learn more

The value of sin square 53 + sin square 37 + sin square 90 degree​

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