Question

sin? 2
t sin²78=1
LHS sine (go-78)
tsinado
Cas²z8 & sinago
I RHS [sin2+ cos² -1]​

Answer 1

Answer:

sin8θ−cos 8θ

=(sin 4θ−cos 4θ)(sin 4θ+cos 4θ)

=(sin 2θ−cos

2θ)(sin 2θ+cos 2θ)((sin 2 θ+cos 2θ) 2−2sin 2θ.cos 2θ)

=(sin 2θ−cos 2θ)(1−2sin 2θ.cos 2θ)

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