Math, asked by anant6, 1 year ago

sin^2 theta -2 cos theta+1/4 =0
find value(°) of theta

Answers

Answered by leninviki
5
theta=60°
sin60°=√3/2
cos60°= 1/2
(√3/2)^2-2(1/2)+1/4
(3/4)-1+(1/4)
=0

anant6: can we do assumption of (°)
anant6: tell me man
anant6: leninviki
leninviki: apply theta value 0,30,45,60°
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