Math, asked by donald756, 2 months ago

sin^ 2 theta c1+cot^ 2 theta )=1​

Answers

Answered by Anonymous
2

Answer:

LHS=(sinA+secA)

2

+(cosA+cosecA)

2

=sin

2

A+2sinAsecA+sec

2

A+cos

2

A+2cosAcosecA+cosec

2

A

=(sin

2

A+cos

2

A)+(sec

2

A+cosec

2

A)+2sinAsecA+2cosAcosecA

=1+(

cos

2

A

1

+

sin

2

A

1

)+2

cosA

sinA

+2

sinA

cosA

(∵sin

2

A+cos

2

A=1)

=1+(

cos

2

Asin

2

A

sin

2

A+cos

2

A

)+2(

cosAsinA

sin

2

A+cos

2

A

)

=1+(

cos

2

Asin

2

A

1

)+2(

cosAsinA

1

)

=1+sec

2

Acosec

2

A+2secAcosecA

=(1+secAcosecA)

2

=RHS

hope it helps you

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