Question

sin^2 theta +cos^2theta /sec^2 theta -tan^2theta =1​

Answer 1

Answer:

sin^2 theta +cos^2theta /sec^2 theta -tan^2theta =1

solution :

sin^2 theta + cos^2 theta = 1

sec^2 theta- tan^2 theta = 1

so according to the question

1 / 1 = 1

hence PROVED

hope it helps

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Answer 2

${ \sin(?) }^{2} + { \cos(?) }^{2} = 1 \\ { \sec(?) }^{2} - { \tan(?) }^{2} = 1 \\ \frac{1}{1} = 1$

hope.it will help you.

let?=thetha