Question

sin 2 theta is equal to 2 tan theta upon 1 + tan square theta and theta =30 degree​

Answer 1

here is ur solution for your question

Answer 2

Given :

$\sin2\theta=\frac{2\tan\theta}{1+\tan^2\theta}$

Step-by-step explanation:

$\theta = 30^\circ \\\\\text{taking LHS}\\\\ \sin2\theta = 2 \sin\theta \cos \theta \\\\2\times \frac{1}{2}\times\frac{\sqrt{3}}{2}\\\\\sin 2\theta = \frac{\sqrt{3}}{2}\\\\\text{taking RHS}\\\\\frac{2\tan\theta}{1+\tan^2\theta}\\\\\frac{2\tan30^\circ}{1+\tan 30^\circ}\\\\\frac{\frac{2}{\sqrt{3}}}{1+\frac{1}{3}}\\\\\frac{\sqrt{3}}{2}=LHS$

LHS = RHS

hence proved

#Learn more :

https://brainly.in/question/14860493