Math, asked by ashokgovindu889, 11 months ago

sin 20.sin40.sin60.sin80=3/16
prove it.​

Answers

Answered by Anonymous
1

Answer:

please refer above attachment for answer

Attachments:
Answered by ak2820143
1

Answer:

sin20.sin40.sin60.sin80

Step-by-step explanation:

sin 60[sin20 .sin40 .sin80]

√3/2[sin20 .sin(60-20) .sin(60+20)]

√3/2[sin3 (20)/4]

√3/2[ sin60/4]

√3/2 [√3 /2*4]

√3/2*√3/8

3/16

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