Math, asked by gulshaara1002, 3 months ago

(Sin 20°/Cos 70°)^2 (Cos 62°/Sin28°)^2
- Sin^2 30°​

Answers

Answered by anurag2147
4

Answer:

(Sin 20°/Cos 70°)² (Cos 62°/Sin28°)²

- Sin² 30°

(sin20/cos90-20)²(cos62/sin90-62)²-sin²30

(sin20/sin20)²(cos62/cos62)²-sin²30

1²×1²- (1/2)²

1 - 1/4 = 4-1/4 = 3/4

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