Question

sin? 2020° + cos2020° + tan 50°
sec 2019
tan
2 2019° + cot 40°
4
3
2
1
ve Neyt​

Answer 1

Answer:

Hello mate ✌️

Step-by-step explanation:

Sec 42/cosec 48 ➕ 3 tan 50/cot 40 - 2 cos 43/sin 47

= sec (90-48)/cosec48+ 3tan50/cot(90-50) -2cos43/sin(90-43)

=cosec48/cosec48+3tan50/tan50-2cos43/cos43

=1+3-2 (The trigonometrical ratios get cancelled)

=2 (Ans.)

Formula:

sec(90-theta)=cosec theta

tan(90-theta)= cot theta.

hope it will be helpful to you ✌️

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