Math, asked by Bgmi72, 19 days ago

sin 22° = 1/cosec(90-Thita)​

Answers

Answered by lakshmanadatta
1

Answer:

68

Step-by-step explanation:

 cosec(90−θ)=\frac{1}{sin22}°

cosec(90−θ)= \frac{1}{sin22}°  

 

cosec(90−θ)=cosec22°

 

So 90−θ=22°  

 

θ=90−22

θ=68°  

Answered by Frank7652
0

sin22° = 1/cosec (90-theta)

sin22° = sin (90-theta)

sin22° = cos theta

thita = sin22°/cos

theta = tan22°

hope it helps you

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