sin 22° = 1/cosec(90-Thita)
Answers
Answered by
1
Answer:
68
Step-by-step explanation:
cosec(90−θ)=°
cosec(90−θ)= °
cosec(90−θ)=cosec22°
So 90−θ=22°
θ=90−22
θ=68°
Answered by
0
sin22° = 1/cosec (90-theta)
sin22° = sin (90-theta)
sin22° = cos theta
thita = sin22°/cos
theta = tan22°
hope it helps you
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