sin^222°+sin^268°\cos^222°+cos^268° sin^263°+cos63°.sin27°
Aditi444444:
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Plss chk, is there any mistake in the question which I have written
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Answer:
=
cos
2
22
o
+cos
2
(90
o
−22
o
)
sin
2
22
o
+sin
2
(90
o
−22
o
)
+sin
2
63
o
+cos63
o
×sin(90
o
−63
o
)
=
cos
2
22
o
+sin
2
22
o
sin
2
22
o
+cos
2
22
o
+sin
2
63
o
+cos63
o
×cos63
o
( as we know sin(90
o
−θ)=cosθ and cos(90
o
−θ)=sinθ)
=
1
1
+sin
2
63
o
+cos
2
63
o
=1+1
=2
∴
(cos
2
22
o
+cos
2
68
o
)
(sin
2
22
o
+sin
2
68
o
)
+sin
2
63
o
+cos63
o
sin27
o
= 2 will be the answer
Step-by-step explanation:
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