Question

sin^230°+ cos^260°+tan^245°+ sec^60° - cosec 30°=​

Answer 1

Question: Find the value of $sin^230^0+cos^260^0+tan^245^0+sec60^0-cosec30^0$.

Answer:

The required answer is 3/2.

Step-by-step explanation:

Step 1 of 2

Consider the given trigonometric function as follows:

$sin^230^0$ + $cos^260^0$ + $tan^245^0$ + sec60° - cosec30° . . . . . (1)

The value of $sin^230^0$ is:-

• sin30° = 1/2

       Squaring both the sides.

       ⇒ $sin^230^0$ = 1/4

The value of $cos^260^0$ is:-

• cos60° = 1/2

        Squaring both the sides.

        ⇒ $cos^260^0$ = 1/4

The value of $tan^245^0$ is:-

• tan45° = 1

       Squaring both the sides.

       ⇒ $tan^245^0$ = 1

The value of sec60° is:-

• sec60° = 2

The value of cosec30° is:-

• cosec30° = 2

Step 2 of 2

Substitute all the values of trigonometric angles in the (1) as follows:

⇒ $\frac{1}{4}+\frac{1}{4}+1+2-2$

⇒ $\frac{2}{4} +1$

⇒ $\frac{2+4}{4}$

⇒ 6/4

⇒ 3/2

Thus, the required answer is 3/2.

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