Math, asked by saramasurkar13, 12 hours ago

sin ²35° + sin ² 55° + tan 25°-cosec 65​

Answers

Answered by achuaku4
1

Answer:

If the question is bracket one then the answer is 1.As. cos15*sin25/cos25*sin60/ cos60*sin65/cos65*sin75/ cos75 [as tan15 =sin15/ cos15]. Sin15/cos15*sin25/ cos25*sin60/cos60*sin(90-25)/ Sin15/cos15*sin25/cos25*sin60/ cos60*cos25/sin25*cos15/ sin15. [Now on solving we get]. √3/2*2/√3 =1

Step-by-step explanation:

I think it is right answer pls confirm

Answered by curi6810
0

Answer:

1+tan 25°-cosec 65°

Step-by-step explanation:

sin ²35° + sin ² 55° + tan 25°-cosec 65°

=1+tan 25°-cosec 65°

=0.36293

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