sin(240+theta)+cos(30-theta)
can anyone help me to do this question
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What is the value of sin (60+ theta)-cos (30-theta)?
Let theta be equal to x.
sin ( 60°+x)
= sin 60.cos x + cos 60.sinx
=[(√3 cos x) /2 + (1 sin x) /2]
cos (30 - x)
= cos 30.cos x + sin 30.sin x
=[ (√3 cos x) /2 + (1 sin x) /2]
Therefore, sin ( 60 + x) - cos ( 30 - x)
= [(√3 cos x) /2 + (1 sin x) /2] - [(√3 cos x) /2 + (1 sin x) /2]
= 0
The answer is 0
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