Question

sin 25 degree/sec 65degree+cos 25degree/cosec 65degree

Answer 1

Given, (sin 25 / sec 65) + (cos 25 / cosec 65)

= (sin 25 * cos 65) + (cos 25 * sin 65)

= (sin 25 * cos (90 - 25)) + (cos 25 * sin(90 - 25))

= (sin 25 * sin 25) + (cos 25 * cos 25)        (w.k.t cos (90-theta) = sin theta)

= (sin^2 25 + cos^2 25) = 1                 (we know that sin^2theta+cos^2theta = 1)


Hope this helps!

Answer 2

I think the answer is this Sir