sin 25 degree/sec 65degree+cos 25degree/cosec 65degree
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Given, (sin 25 / sec 65) + (cos 25 / cosec 65)
= (sin 25 * cos 65) + (cos 25 * sin 65)
= (sin 25 * cos (90 - 25)) + (cos 25 * sin(90 - 25))
= (sin 25 * sin 25) + (cos 25 * cos 25) (w.k.t cos (90-theta) = sin theta)
= (sin^2 25 + cos^2 25) = 1 (we know that sin^2theta+cos^2theta = 1)
Hope this helps!
= (sin 25 * cos 65) + (cos 25 * sin 65)
= (sin 25 * cos (90 - 25)) + (cos 25 * sin(90 - 25))
= (sin 25 * sin 25) + (cos 25 * cos 25) (w.k.t cos (90-theta) = sin theta)
= (sin^2 25 + cos^2 25) = 1 (we know that sin^2theta+cos^2theta = 1)
Hope this helps!
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I think the answer is this Sir
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