Question

sin(250 +).cos(250-0) - cos(25° +)
.sin(250 - 0)=sin(0+0)​

Answer 1

Answer:

$sin(250+\theta).cos(250-\theta)- cos(250+\theta).sin(250-\theta)=sin(2\theta)$

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Step-by-step explanation:

Formula used:

$\bold{sin(A-B)=sinA\:cosB-cosA\:sinB}$

Given:

$sin(250+\theta).cos(250-\theta)- cos(250+\theta).sin(250-\theta)$

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$=sin[(250+\theta)-(250-\theta)]$

$=sin[250+\theta-250+\theta]$

$=sin[\theta+\theta]$

$=sin(2\theta)$