Question

(Sin 26 /sec 64)+(cos26/cosec64)=2

Answer 1

Lhs =sin26/sec64 +(cos26/cosec64)

=sin26/sec(90-26) + cos26/cosec(90-26)
=sin26/cosec26 +cos26/sec26
=sin26*sin26+cos26*cos26
=sin^2(26)+ cos^2(26)
=1

Answer 2

(sin 26/sec 64) + (cos 26/cosec 64)

We know that ;
---> cosA = 1/secA &. sinA = 1/cosecA

= (sin26 × cos64) + (cos26 × sin64)
---------------> sinA = cos(90-A)

= [sin26 × sin(90-64)] + [cos26 × cos(90-64)]

= (sin26 × sin26) + (cos26×cos26)

= sin^2(26) + cos^2(26)
-----------------> sin^2A + cos^2A = 1
= 1
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