sin^263+sin^227÷cos^217+cos^273
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Answer:
(Sin²63 + Sin²27 ) /(Cos²17 + Cos²73) = 1
Step-by-step explanation:
(Sin²63 + Sin²27 ) /(Cos²17 + Cos²73)
As we know that
Sin(90 - θ) = Cosθ
&Cos(90 - θ) = Sinθ
= (Sin²(90 - 27) + Sin²27 )) /(Cos²17 + Cos²(90 - 17))
= (Cos²27 + Sin²27 )) /(Cos²17 + Sin²17)
We know that Sin²θ + Cos²θ = 1
=> Cos²27 + Sin²27 = 1
Cos²17 + Sin²17 = 1
= 1/1
= 1
(Sin²63 + Sin²27 ) /(Cos²17 + Cos²73) = 1
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