Math, asked by anamikaiyengar84971, 10 months ago

Sin(270-x)=cos292 ,find x in (0,2π)

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Answered by Anonymous

8

Answer:

$\sin(270 - x) = \cos(292) \\ \sin(270 - x) = \cos(270 + 22) \\ \sin(270 - x) = \sin(22) \\ 270 - x = 22 \\ x = 270 + 22 = 292$

Hope its help uh❤

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