Math, asked by lakshya243738, 11 months ago

(sin 28° 54'/sec 61°6') + (cos28°54'/cosec61°6')​

Answers

Answered by ravikantjangir459
21

Step-by-step explanation:

sec 61° 6'= 1/cos61°6'

cosec 61°6'=1/sin61°6'

sin(a+b)=sin(a)cos(b) + cos(a)sin(b)

above equation can be written by

sin28°54'cos61°6' + cos 28°54'sin61°6'

sin(28°54'+61°6')=sin(90°)=1 answer.

Answered by probaldas70
2

Answer:

can you please send an image

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