Math, asked by jadhavrina14, 4 months ago

sin^2A/2+sin^2B/2-sin^2C/2=1-2cosA/2×cosB/2×cosC/2

Answers

Answered by sakibulmandal

0

Answer:

sin^2A/2+sin^2B/2-sin^2C/2=1-2cosA/2×cosB/2×cosC/2

Step-by-step explanation:

sin^2A/2+sin^2B/2-sin^2C/2=1-2cosA/2×cosB/2×cosC/2

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