Sin 2A = 2 sin A is true when A =
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Answer:
sin2A=2sinA
⇒2sinAcosA=2sinA
⇒2sinA(cosA−1)=0
⇒sinA=0,cosA−1=0
⇒sinA=0,cosA=1
sinA=0⇒A=0,π,2π
cosA=1⇒A=0,2π
∴A={0,π,2π}∩{0,2π}
=0 and 2 π
A = 0
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