Question

sin 2A = 2 sin A is true when A= (B) 30° (A) 0° 2 tan 30° (iv) 2 II. 1 - tan' 30° ( A) cos 60° (B) sin 60°​

Answer 1

Answer: Hey Friend

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Step-by-step explanation:

1) sin 2A = 2 sin A

sin 2 ( 0 ) = 2 sin ( 0 ) taking the value zero

0 = 0

so , 0°

2)  i think the second q was 2tan 30°/ 1- tan²30°

so , 2 X 1/root 3/1 + 1/(root 3)² = 2/root 3 / 4 /3

= root 3 / 2 /3 ----------------after cancelling 4 with 2

=3 /2 root 3 ---------- taking 2 up

= 3 X root 3/2 root 3 X  root 3 ------------------------------ rationalizing

3 X root 3 / 2 X 3 = root 3/2----------------------------- cancelling 3

a) sin 60°