sin^2A+2sinA+1=0 ,then find value ofA.
Answers
Answered by
0
Step-by-step explanation:
Given, 2sinA−1=0
sinA=1/2
sinA=sin30
o
∴A=30
o
Now, (LHS)
sin3A=sin(3×90
o
)
=sin90
o
=1
(RHS) =3sinA−4sin
3
A
⇒3sin30
o
−4sin
3
(30
o
)
⇒3×
2
1
−4×(
2
1
)
3
2
3
−
8
4
=
2
3−1
=1
∴ LHS=RHS=1 Proved
Answered by
0
Step-by-step explanation:
given is 2a + 2s in A + 1 = 0
since A = 1/2
A = ????
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