sin(2A+45)=cos (30-A) then find a
Answers
Answered by
44
aloha user✋☺️
sin( 2A + 45° ) = cos ( 30° - A )
sin ( 2A + 45° ) = sin ( 90° - ( 30° - A))
sin ( 2A + 45° ) = Sin ( 90° - 30° + A )
2A + 45 = 60° + A
2A - A = 60° - 45°
A = 15°
hope it helps !!
good life !!
sin( 2A + 45° ) = cos ( 30° - A )
sin ( 2A + 45° ) = sin ( 90° - ( 30° - A))
sin ( 2A + 45° ) = Sin ( 90° - 30° + A )
2A + 45 = 60° + A
2A - A = 60° - 45°
A = 15°
hope it helps !!
good life !!
Answered by
17
Sol
Given that sin (2a45°) =cos (30-a°)
Sin (2a+45°) =sin (90-(30-a°)
2a+45°=60°+a
A=15°....
Given that sin (2a45°) =cos (30-a°)
Sin (2a+45°) =sin (90-(30-a°)
2a+45°=60°+a
A=15°....
Similar questions