Question

Sin^2A-cos^2A.cos2B=sin^2B-cos^2B.cos2A prove it

Answer 1

Step-by-step explanation:

sin^2A×cos2B - sin^2B×cos2A 

= sin^2 A ( cos^2 B - sin^2 B) - sin^2 B ( cos^2 A - sin^2 A) 

= sin^2 A cos^2 B - sin^2 A sin^2 B - sin^2 B cos^2 A + sin^2 B sin^2 A 

= sin^2 A cos^2 B - sin^2 B cos^2 A 

= (1-cos^2 A) cos^2 B - (1-cos^2 B) cos^2 A 

= cos^2 B - cos^2 A cos^2 B - cos^2 A + cos^2B cos^2 A 

= cos^2 B - cos^2 A

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Answer 2

Answer:

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Step-by-step explanation:

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