Question

sin^2A-cos^2A*cos2B=sin^2B-cos^B*cos2A​

Answer 1

Answer:

hii frnd

Step-by-step explanation:

answe is

Sin^2A×cos2B - sin^2B×cos2A 

= sin^2 A ( cos^2 B - sin^2 B) - sin^2 B ( cos^2 A - sin^2 A) 

= sin^2 A cos^2 B - sin^2 A sin^2 B - sin^2 B cos^2 A + sin^2 B sin^2 A 

= sin^2 A cos^2 B - sin^2 B cos^2 A 

= (1-cos^2 A) cos^2 B - (1-cos^2 B) cos^2 A 

= cos^2 B - cos^2 A cos^2 B - cos^2 A + cos^2B cos^2 A 

= cos^2 B - cos^2 A