sin 2A.cos 2A.cosec 2A
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answer is cos2A it is easy because cosecx=1/sinx
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ʜᴇʏᴀ!!
ʜᴇʀᴇ's ʏᴏᴜʀ ᴀɴsᴡᴇʀ
_____________________
sɪɴ 2ᴀ . ᴄᴏs 2ᴀ . ᴄᴏsᴇᴄ 2ᴀ
= sɪɴ 2ᴀ . ᴄᴏs 2ᴀ . 1 / sɪɴ 2ᴀ [ • ᴡᴇ ᴋɴᴏᴡ , sɪɴ ᴀ= 1 / ᴄᴏsᴇᴄᴀ ]
= ᴄᴏs 2ᴀ
_____________________
ʜᴏᴘᴇ ɪᴛ ʜᴇʟᴘs ʏᴏᴜ ᴅᴇᴀʀ! :)
★ ᴅᴇᴠɪʟ ᴋɪɴɢ
ʜᴇʀᴇ's ʏᴏᴜʀ ᴀɴsᴡᴇʀ
_____________________
sɪɴ 2ᴀ . ᴄᴏs 2ᴀ . ᴄᴏsᴇᴄ 2ᴀ
= sɪɴ 2ᴀ . ᴄᴏs 2ᴀ . 1 / sɪɴ 2ᴀ [ • ᴡᴇ ᴋɴᴏᴡ , sɪɴ ᴀ= 1 / ᴄᴏsᴇᴄᴀ ]
= ᴄᴏs 2ᴀ
_____________________
ʜᴏᴘᴇ ɪᴛ ʜᴇʟᴘs ʏᴏᴜ ᴅᴇᴀʀ! :)
★ ᴅᴇᴠɪʟ ᴋɪɴɢ
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