Sin^2A.cos^2B-cos^2A.sin^2B=?
Answers
Answered by
1
Answer:
Step-by-step explanation:
=sin(2A-2B)
....................................................................
golujaat431:
Sin(A+B).Sin(A-B)
Answered by
0
Sin^2A.cos^2-cos^2A.sin^2B
= (SinAcoosB+cosAsinB)(sinAcosB-cosAsinB)
= sin (A+B).sin (A-B)
=sin^2A -sin^2B
= (SinAcoosB+cosAsinB)(sinAcosB-cosAsinB)
= sin (A+B).sin (A-B)
=sin^2A -sin^2B
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