sin^2A cos^2B + cos^2A sin^2B + cos^2A cos^2 B+ sin^2A sin^2B =1
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to prove
Sin^2A cos^2B + cos^2A sin^2B + cos^2A cos^2 B+ sin^2A sin^2B =1\
so--
(Sin^2A cos^2B + cos^2A sin^2B0 + 9cos^2A cos^2 B+ sin^2A sin^2B)
=1
=sin^2(a+b)+cos^2(a+b)
so sin^2a +cos^2a=1
soSin^2A cos^2B + cos^2A sin^2B + cos^2A cos^2 B+ sin^2A sin^2B =1
falgunivarma:
can u explain 2nd step again and also the third one
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