Math, asked by khushi2921, 10 months ago

sin^2A cos^2B + cos^2A sin^2B + cos^2A cos^2B + sin^2A sin^2B = 1

Answers

Answered by spiderman2019
1

Answer:

Step-by-step explanation:

sin²A cos²B + cos²A sin²B + cos²A cos²B + sin²A sin²B

= cos²B(sin²A + cos²A) + sin²B(cos²A+ sin²A)

= cos²B + sin²B

= 1

= R,H.S

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