Sin^2A= Please answer quickly
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Sin^2A=1-cos^2A
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Hey there!
We know that,
sin²A + cos²A = 1
sin²A = 1 - cos²A
Also,
tanA = sinA / cosA
sinA = tanA * cosA
Squaring on both sides, We obtain
sin²A = tan²A * cos²A
And,
sinA = 1/cscA
sin²A = 1/csc²A
Next,
cotA = cosA / sinA
sinA = cotA / cosA
sin²A = cot²A / cos²A
So,
sin²A = 1 - cos²A = tan²A * cos²A = cot²A / cos²A
We know that,
sin²A + cos²A = 1
sin²A = 1 - cos²A
Also,
tanA = sinA / cosA
sinA = tanA * cosA
Squaring on both sides, We obtain
sin²A = tan²A * cos²A
And,
sinA = 1/cscA
sin²A = 1/csc²A
Next,
cotA = cosA / sinA
sinA = cotA / cosA
sin²A = cot²A / cos²A
So,
sin²A = 1 - cos²A = tan²A * cos²A = cot²A / cos²A
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