Math, asked by shivamkuar, 9 months ago

sin^2a•sec^2a find the value of a

Answers

Answered by harinivasanthvk

0

Answer:

(sec2A−1)(cosec3A−1)=0

sec2A=1 or cosec3A=1

2A=0 or 3A=90

A=0 or A=30∘

Thus, A=0∘or30∘

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