Math, asked by RajDipti1, 1 year ago

sin^2A+sin^2B =1 prove it

Answers

Answered by TheLifeRacer
5
Hey friend ..

As you know that in right angle triangle there is 3 side , heipotenous h` base `b and p perpendicular.

So, by using Pythagoras theorem you know

h²=p²+b²----------1)

and, now you know sin¢=p/h
and ,
cos¢=b/h

so,, now putting this value on

sin²¢+cos²¢

=(p/h)²+(b/h)²

=p²+b²/h²

=h²/h². {by using 1 . equation}

=1 RHS prooved .

hope it helps you .

#Rajukumar111

RajDipti1: thanks a lot bhai you solve my problem
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