sin^2A+sin^2B =1 prove it
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Hey friend ..
As you know that in right angle triangle there is 3 side , heipotenous h` base `b and p perpendicular.
So, by using Pythagoras theorem you know
h²=p²+b²----------1)
and, now you know sin¢=p/h
and ,
cos¢=b/h
so,, now putting this value on
sin²¢+cos²¢
=(p/h)²+(b/h)²
=p²+b²/h²
=h²/h². {by using 1 . equation}
=1 RHS prooved .
hope it helps you .
#Rajukumar111
As you know that in right angle triangle there is 3 side , heipotenous h` base `b and p perpendicular.
So, by using Pythagoras theorem you know
h²=p²+b²----------1)
and, now you know sin¢=p/h
and ,
cos¢=b/h
so,, now putting this value on
sin²¢+cos²¢
=(p/h)²+(b/h)²
=p²+b²/h²
=h²/h². {by using 1 . equation}
=1 RHS prooved .
hope it helps you .
#Rajukumar111
RajDipti1:
thanks a lot bhai you solve my problem
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