Question

sin^2a+sin^2b.cos2a=sin^2b+sin^2a.cos2a​

Answer 1

Answer:

LHS=(sinAcosB)2−(cosAsinB)2

       =(sinAcosB+cosAsinB)(sinAcosB−cosAsinB)

       =sin(A+B)sin(A−B)

       =sin2A−sin2B

   

       =RHS

Hence proved