Math, asked by mudigallusreenivas20, 7 months ago

sin^2A+sin^2B-sin²c = 1-2sinAsinBsinC

Answers

Answered by deepikaarya

0

Step-by-step explanation:

If A+B+C=π/2, Prove that sin^2A+sin^2B+sin^2C=1- 2sinAsinBsinC?

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