Question

sin 2A = sin 2B to prove that triangle ABC is an isosceles triangle​

Answer 1

Answer:

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Answer 2

The triangle ABC is an isosceles triangle, proved.

Step-by-step explanation:

We have,

$\sin 2A = \sin 2B$

To prove that, the triangle ABC is an isosceles triangle​.

∴ $\sin 2A = \sin 2B$

Using the trigonometric identity,

$\sin ^{-1}\sin {x}=x$

∴ $\sin 2A = \sin 2B$

⇒ 2A $=\sin ^{-1} \sin 2B$

⇒ 2A = 2B

⇒ ∠ A = ∠ B

The two angles of triangle ABC are equal.

∴ The triangle ABC is an isosceles triangle, proved.

Hence, the triangle ABC is an isosceles triangle, proved.