Math, asked by ashokprajapaati, 1 month ago

sin^2A.tan^2A + cos^2A.cot^2A =tan^2A + cot^2A -1​

Answers

Answered by tanvipatade2003
0

Step-by-step explanation:

LHS = sin^2A.tan^2A + cos^2A.cot^2A

= sin^2A.(sec^2A - 1)+cos^2A.(cosec^2A-1)

= sin^2A.(1/cos^2A - 1)+cos^2A.(1/sin^2A - 1)

= (sin^2A/cos^2A) - sin^2A +(cos^2A/sin^2A)

- cos^2A

= tan^2A - sin^2A + cot^2A - cos^2A

= tan^2A+ cot^2A -(sin^2A+cos^2A)

= tan^2A+ cot^2A - 1

= RHS

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