Math, asked by raja6688, 1 year ago

sin 2A =?, when sinA=12/13

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Answers

Answered by Agastya0606
1

The correct answer to this question is \frac{120}{169}.

Given,

sinA=\frac{12}{13}

To Find,

sin2A.

Solution,

As we know that

sin2A=2SinAcosA

So,

sinA=\frac{P}{H}

So, here sinA=\frac{12}{13}

cosA=\frac{B}{H}

By using the Pythagoras theorem

B²=H²-P²

B²=13²-12²

B²=169-144

B²=25

B=5.

Now, we have values of P, H, and B.

cosA=\frac{5}{13}.

Then,

sin2A=2×\frac{12}{13}×\frac{5}{13}.

=\frac{2*12*5}{13*13}.

=\frac{120}{169}.

The correct answer to this question is\frac{120}{169}.

#SPJ2

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