sin 2A =?, when sinA=12/13
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The correct answer to this question is .
Given,
sinA=
To Find,
sin2A.
Solution,
As we know that
sin2A=2SinAcosA
So,
sinA=
So, here sinA=
cosA=
By using the Pythagoras theorem
B²=H²-P²
B²=13²-12²
B²=169-144
B²=25
B=5.
Now, we have values of P, H, and B.
cosA=.
Then,
sin2A=2××.
=.
=.
The correct answer to this question is.
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