Question

sin 2b = 2 cos b is true when b =

Answer 1

Answer:

sin2B=2sinB

sin2θ=2sinθcosθ

2sinBcosB=2sinB

\cos B = \frac{2\sin B }{2\sin B}cosB=

2sinB

2sinB

\begin{gathered}\cos B =1\\\\\cos B = 0\\\\\angle B = 0^\circ\end{gathered}

cosB=1

cosB=0

∠B=0