Question

Sin 2B = 2 SinB is true when B is eqal to *​

Answer 1

Answer:

$\: \: \: \: sin \: 2B = 2sin \: B \\ \implies \: 2sin \: B \: . \: cos \: B = 2sin \: B \: \\ \implies \: \: \frac{ \cancel{ 2sin \: B} \: . \: cos \:B }{ \cancel{2sin \:B} } = 1 \\ \implies \: \: cos \: B \: = 1 \\ \implies \: B = {cos}^{ - 1} 1 \\ \implies \: B = {0}^{ \circ}$

Note :

$\green \odot \: sin \: 2 \theta = 2 \: sin \: \theta.cos \: \theta \: \\ \\ \green \odot \: \: cos \: {0}^{ \circ} \: = 1$