Question

sin^2Q +cos^2Q=1 how​

Answer 1

Answer:

Step-by-step explanation:

We know c sin=P/H = a/c

c cos=B/H = b/c          

Multiplying c sin and c cos by c we get c sin = a, c cos = b

By phyth. thrm.

a^2 + b^2 = c^2

therefore  substituting a and b we get,

(c sin)^2 + (c cos)^2 = c^2

c^2 sin^2 + c^2 cos^2 = c^2

c^2( sin^2 + cos^2) = c^2

sin^2 + cos^2 = c^2/c^2 = 1

Hence proved