sin^2theta/costheta+costheta=sectheta
Answers
Answered by
3
LHS
=sin^2theta+cos^2theta/costheta......by taking LCM
=(sin^2theta+cos^2theta=1)
=1/costheta
=sectheta
=RHS
=sin^2theta+cos^2theta/costheta......by taking LCM
=(sin^2theta+cos^2theta=1)
=1/costheta
=sectheta
=RHS
kimparipurna:
hope u understand
Answered by
0
ANSWER:
sin²θ/cosθ + cosθ = secθ
sin²θ+cos²θ/cosθ (lcm is cos θ)
↑(sin²+cos²a=1)
1/cosθ =secθ
LHS = RHS
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